【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
2001/8/19!用对话框提示用户输入基本数据
!:reread
!multipro,'start',3
! *cset,1,3,y_bot,'enter the value of y_bot',0
! *cset,4,6,y_top,'enter the value of y_bot',0
! *cset,7,9,ttype,'enter the value of train type',0 !输入火车活载的类型
!multipro,'end'
y_bot=13.9
y_top=14.1
ttype = 0
*if,ttype,eq,0, then
q1 = 147000 !中-活载
q2 = 92000
q3 = 80000
L1 = 7.5
L2 = 30
*elseif,ttype,eq,1,then
q1 = 0
q2 = 0
q3 = 0
L1 = 0
L2 = 0
*else
*msg,ui
error valueof ttype(1 or 2),please enter again
*go,: reread
*endif
!识别桥面过列车的单元，并将单元按节点坐标从小到大排序
lsel,s,loc,y,y_bot,y_top
esll,s ! 选中桥面单元
elmax = elmiqr(0,14)! 最大单元号
ndmax = ndinqr(0,14)! 最大节点号
*dim,eldk,,elmax !存放桥面过车单元
*dim,ndx,,elmax !存放过车单元的节点x坐标（两节点坐标中的较小值）
*dim,nodes,,ndmax !存放桥面过车的节点
j=0
*do,i,1,elmax
*if,esel(i),gt,0, then
j = j+1
eldk(j) = i
*endif
*enddo !记录桥面单元的标号，保存于数组eldk中
eldknum = j !总桥面单元数
!对eldk数组排序，按节点坐标从小到大排列
*do,i,1,eldknum
ii = eldk(i)
ndi = nelem(ii,1)
ndj = nelem(ii,2)
i1= nx(ndi)
i2= nx(ndj)
ndx(i) = i1
*if,i2,lt,i1,then
ndx(i) = i2
*endif
*enddo
*do,i,1,eldknum-1
*do,j,i+1,eldknum
*if,ndx(j),lt,ndx(i),then
temp = ndx(i)
ndx(i) = ndx(j)
ndx(j) = temp
temp = eldk(i)
eldk(i)= eldk(j)
eldk(j)= temp
*endif
*enddo
*enddo
nsle,s ! 选中桥面单元的节点
j=0
*do,i,1,ndmax
*if,nsel(i),gt,0,then
j=j+1
nodes(j)=i
*endif
*enddo
ndnum = j ! 总桥面节点数
xmin = nx(nelem(eldk(1),1))
temp = nx(nelem(eldk(1),2))
*if,temp,lt,xmin,then
xmin = temp
*endif
xmax = nx(nelem(eldk(eldknum),1))
temp = nx(nelem(eldk(eldknum),2))
*if,temp,gt,xmax,then
xmax = temp
*endif
qth = xmax -xmin ! 桥面过车长度
lth1 = 2*qth + L1+L2 +182.5
lth= (nint(lth1/5)+8)*5 !总长度
dim = lth/5 +1
*dim,disy,table,dim,ndnum !桥面节点的y方向的位移值
*dim,disy1,table,dim,ndnum !桥面节点的y方向的位移值(从大到小)
*dim,disx,table,dim,ndnum !桥面节点的x方向的位移值
*dim,disa,table,dim,ndnum !桥面节点的转角
*dim,disymax,,ndnum
*dim,diy,table,dim
*dim,ffx,table,elmax,dim !单元轴力
*dim,fmz,table,elmax,dim !单元弯矩
*dim,detaf,,elmax !每个单元轴力变化值
*dim,detaf1,,elmax !每个单元轴力变化值（从小到大）
*dim,elnum,,elmax !轴力变化最大的单元号
*dim,detaf2,,20 !前20个轴力变化最大值
*dim,elnum2,,20 !前20个轴力变化最大值的单元
*dim,fmax,,elmax !每个单元的轴力最大值
*dim,fmin,,elmax !每个单元的轴力最小值
*dim,fabs,,elmax !每个单元轴力最大值（绝对值）
*dim,elnum3,,elmax !轴力最大的单元号
*dim,elnum4,,20 !前20个轴力最大的单元号
*dim,nmax,,20
*dim,dfmaxel,table,dim,20 !前20各轴力变化最大单元的轴力
*dim,dmmaxel,table,dim,20 !前20各轴力变化最大单元的弯矩
*dim,fmaxel,table,dim,20 !前20各轴力最大单元的轴力
*dim,mmaxel,table,dim,20 !前20各轴力最大单元的弯矩
eplot ! plot element
allsel
time = 0
*do,kk,0,lth,5,
time = time+1
!/uis,msgpop,3 ! 不显示数组被重新定义的警告
!/uis,msgpop,2
/solu !进入求解器
antype,static
esel,all
sfedele,all,1,pres, !先删除上一次加上的所有单元荷载
! 计算列车各部分在桥上的单元号
tpos1 = kk ! 火车头所在的位置
*if,tpos1,lt,(qth+L1+L2), then!火车进桥情况
xlth1 = 0
*do,i,1,eldknum
ii= eldk(i)
ndi = nelem(ii,1)
ndj = nelem(ii,2)
elth1 = abs(nx(ndi)-nx(ndj))
xlth1 = xlth1 + elth1
*if,xlth1,ge,tpos1,then
*exit
*endif
*enddo
tele1 =i ! 火车头所在的单元
*if,tpos1,gt,L1,then
tpos2 =tpos1 -L1!煤水车头所在的位置
xlth2 = 0
*do,i,1,eldknum
ii= eldk(i)
ndi = nelem(ii,1)
ndj = nelem(ii,2)
elth2 = abs(nx(ndi)-nx(ndj))
xlth2 = xlth2 + elth2
*if,xlth2,ge,tpos2,then
*exit
*endif
*enddo
tele2 = i !旅客列车头所在的单元
*if,tpos1,gt,(L1+L2),then
tpos3 =tpos1 -(L1+L2)!旅客车头所在的位置
xlth3 = 0
*do,i,1,eldknum
ii= eldk(i)
ndi = nelem(ii,1)
ndj = nelem(ii,2)
elth3 = abs(nx(ndi)-nx(ndj))
xlth3 = xlth3 + elth3
*if,xlth3,ge,tpos3,then
*exit
*endif
*enddo
tele3 = i !旅客列车头所在的单元
*endif
*endif
*endif
*if,tpos1,gt,(qth+L1+L2+182.5),then! 火车过桥情况(182.5为任意取的一个常数)
*if,tpos1,lt,lth1, then
tpos4 = tpos1-(qth+L1+L2+182.5) !旅客列车尾部所在的位置
xlth4 = 0
*do,i,1,eldknum
ii= eldk(i)
ndi = nelem(ii,1)
ndj = nelem(ii,2)
elth4 = abs(nx(ndi)-nx(ndj))
xlth4 = xlth4 + elth4
*if,xlth4,ge,tpos4,then
*exit
*endif
*enddo
tele4 = i !旅客列车尾部在的单元
*endif
*endif
! 加荷载于相应的单元
!SFBEAM, ELEM, LKEY, Lab, VALI, VALJ, VAL2I, VAL2J, IOFFST, JOFFST
*if,tpos1,le,L1, then ! 火车头进桥
c1 = xlth1 -tpos1
c2 = elth1 - c1
*if,tele1,eq,1,then
qq = q1*c2/elth1
sfbeam,eldk(tele1),1,pres,qq,qq,,,,,
*else
*do,j,1,tele1-1
sfbeam,eldk(j),1,pres,q1,q1,,,,,
*enddo
qq = q1*c2/elth1
sfbeam,eldk(tele1),1,pres,qq,qq,,,,,
*endif
*elseif,tpos1,le,(L1+L2),then ! 煤水车进桥
c1 = xlth1 - tpos1
*if,tele1,eq,tele2,then!火车头在同一个单元上
c2 = xlth2 - tpos2
c3 = elth2 - c2
qq = (q1*L1+q2*c3)/elth1
sfbeam,eldk(tele1),1,pres,qq,qq,,,,,
*do,j,1,tele1-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
*else
dtele = tele1 - tele2
*if,dtele,eq,1, then
c2 = xlth2 - tpos2
c3 = elth2 - c2
qq0 = q1*(elth1-c1)/elth1
qq = (q1*c2+q2*c3)/elth2
sfbeam,eldk(tele1),1,pres,qq0,qq0,,,,,
sfbeam,eldk(tele2),1,pres,qq,qq,,,,,
*do,j,1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
*else
c2 = xlth2 - tpos2
c3 = elth2 - c2
qq0 = q1*(elth1-c1)/elth1
sfbeam,eldk(tele1),1,pres,qq0,qq0,,,,,
*do,j,tele2+1,tele1-1
sfbeam,eldk(j),1,pres,q1,q1,,,,,
*enddo
qq = (q1*c2+q2*c3)/elth2
sfbeam,eldk(tele2),1,pres,qq,qq,,,,,
*do,j,1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
*endif
*endif
*elseif,tpos1,le,qth,then ! 旅客列车进桥
c1 = xlth1 - tpos1
*if,tele1,eq,tele2, then
c2 = xlth2 - tpos2
c3 = elth2 - c2
qq = (q1*L1+q2*c3)/elth1
sfbeam,eldk(tele1),1,pres,qq,qq,,,,,
c4 = xlth3 - tpos3
c5 = elth3 - c4
dtele1 = tele2 - tele3
*if,dtele1,eq,1,then
qq1 = (q2*c4+q3*c5)/elth3
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*else
*do,j,tele3+1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
qq1 = (q2*c4+q3*c5)/(elth3)
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*endif
*else
dtele1 = tele1 -tele2
*if,dtele1,eq,1,then
c2 = xlth2 - tpos2
c3 = elth2 -c2
qq0 = q1*(elth1-c1)/elth1
sfbeam,eldk(tele1),1,pres,qq0,qq0,,,,,
c4 = xlth3- tpos3
c5 = elth3 - c4
dtele2 = tele2 - tele3
*if,dtele2,eq,0,then
qq0 = (q1*c2+q2*L2+q3*c3)/elth2
sfbeam,eldk(tele2),1,pres,qq0,qq0,,,,,
*do,j,1,tele2-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*elseif,dtele2,eq,1,then
qq0 = (q1*c2+q2*c3)/elth2
sfbeam,eldk(tele2),1,pres,qq0,qq0,,,,,
qq1 = (q2*c4+c3*c5)/elth3
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*else
qq0 = (q1*c2+q2*c3)/elth2
sfbeam,eldk(tele2),1,pres,qq0,qq0,,,,,
*do,j,tele3+1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
qq1 = (q2*c4+q3*c5)/(elth3)
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*endif
*else
c2 = xlth2 - tele2
c3 = elth2 - c2
qq0 = q1*(elth1-c1)/elth1
sfbeam,eldk(tele1),1,pres,qq0,qq0,,,,,
*do,j,tele2+1,tele1-1,
sfbeam,eldk(j),1,pres,q1,q1,,,,,
*enddo
qq = (q1*c2+q2*c3)/(elth2)
sfbeam,eldk(tele2),1,pres,qq,qq,,,,,
dtele2 = tele2 - tele3
*if,dtele2,eq,1,then
qq1 = (q2*c4+q3*c5)/(elth3)
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*else
*do,j,tele3+1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
qq1 = (q2*c4+q3*c5)/(elth3)
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*endif
*endif
*endif
*elseif,tpos1,le,(qth+L1),then !火车头出桥
c1 = tpos1 - qth !火车头出桥长度
dtele1 =eldknum - tele2
*if,dtele1,eq,0,then
c2 = xlth2 - tpos2
c3 = elth2 - c2
qq = (q1*c2+q2*c3)/(elth2)
sfbeam,eldk(tele2),1,pres,qq,qq,,,,,
dtele2 = tele2 - tele3
c4 = xlth3 -tpos3
c5 = elth3 - c4
*do,j,tele3+1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
qq1 = (q2*c4+q3*c5)/elth3
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*elseif,dtele1,eq,1,then
sfbeam,eldk(eldknum),1,pres,q1,q1,,,,,
qq = (q1*c2+q2*c3)/(elth2)
sfbeam,eldk(tele2),1,pres,qq,qq,,,,,
dtele2 = tele2- tele3
c4 = xlth3 - tpos3
c5 = elth3 - c4
*do,j,tele3+1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
qq1 = (q2*c4+q2*c5)/elth3
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*elseif,dtele1,gt,1,then
*do,j,tele2+1,eldknum
sfbeam,eldk(j),1,pres,q1,q1,,,,,
*enddo
qq = (q1*c2+q2*c3)/(elth2)
sfbeam,eldk(tele2),1,pres,qq,qq,,,,,
c4 = xlth3 - tpos3
c5 = elth3 - c4
*do,j,tele3+1,tele2-1
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
qq1 = (q2*c4+q2*c5)/elth3
sfbeam,eldk(tele3),1,pres,qq1,qq1,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*endif
*elseif,tpos1,le,(qth+L1+L2),then !煤水车头出桥
c4 = xlth3 - tpos3
c5 = elth3 - c4
dtele1 = eldknum - tele3
*if,dtele1,eq,0,then
qq = (q2*c4+q3*c5)/elth3
sfbeam,eldk(tele3),1,pres,qq,qq,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*else
*do,j,tele3+1,eldknum
sfbeam,eldk(j),1,pres,q2,q2,,,,,
*enddo
qq = (q2*c4+q3*c5)/elth3
sfbeam,eldk(tele3),1,pres,qq,qq,,,,,
*do,j,1,tele3-1
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*endif
*elseif,tpos1,le,(qth+L1+L2+182.5),then ! 全桥均布列车荷载(182.5为任意取的
常数)
*do,j,1,eldknum
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
*elseif,tpos1,le,lth1,then ! 均布列车荷载出桥
c1 = xlth4 - tpos4
c2 = elth4 - c1
*do,j,tele4+1,eldknum
sfbeam,eldk(j),1,pres,q3,q3,,,,,
*enddo
qq = q3*c1/elth4
sfbeam,eldk(tele4),1,pres,qq,qq,,,,,
*endif
/psf,pres,norm,1
/replot
solve
finish
/post1
diy(time,0) = tpos1
diy(time) = uy(91) ! 得到中间节点的y坐标
*vplot,diy(1,0),diy(1,1) !动态显示中间节点位移结果
disx(time,0) = tpos1
disy(time,0) = tpos1
disa(time,0) = tpos1
*do,j,1,ndnum
disx(0,j) = nodes(j)
disy(0,j) = nodes(j)
disa(0,j) = nodes(j)
disx(time,j) = ux(nodes(j))
disy(time,j) = uy(nodes(j))
disa(time,j) = rotz(nodes(j))
*enddo
etable,forcex,smisc,1 ! 定义单元轴力表
etable,momentz,smisc,6 ! 定义单元弯矩表
*vget,ffx(1,time),elem,1,etab,forcex,,,,
*vget,fmz(1,time),elem,1,etab,momentz,,,,
ffx(0,time) = tpos1
fmz(0,time) = tpos1
*if,time,eq,1,then
*do,j,1,elmax
ffx(j,0) = j
fmz(j,0) = j
*enddo
*endif
*enddo
save,,,,all
! 结果处理
*do,i,1,ndnum
nd = nodes(i)
disymax(i) = abs(disy(1,nd))
*do,j,2,dim
*if,abs(disy(j,nd)),gt,disymax(i),then
disymax(i) = abs(disy(j,nd))
*endif
*enddo
*enddo
*do,i,1,ndnum-1
*do,j,i+1,ndnum
*if,disymax(j),gt,disymax(i),then
temp = disymax(i)
disymax(i) = disymax(j)
disymax(j) = temp
temp = nodes(i)
nodes(i) = nodes(j)
nodes(j) = temp
*endif
*enddo
*enddo
*do,i,1,ndnum ! 前5个位移最大的节点
numnd = nodes(i)
disy1(0,i) = numnd
*do,j,1,dim
kk = (j-1)*5
disy1(j,0) = kk
disy1(j,i) = disy(kk,numnd)
*enddo
*enddo
*do,i,1,elmax
fmin(i) = ffx(i,1)
fmax(i) = ffx(i,1)
*do,j,2,dim
*if,ffx(i,j),gt,fmax(i),then
fmax(i) = ffx(i,j)
*endif
*if,ffx(i,j),lt,fmin(i),then
fmin(i) = ffx(i,j)
*endif
*enddo
detaf(i) = fmax(i) - fmin(i) ! 每个单元的内力变化值
detaf1(i) = detaf(i)
*enddo
*do,i,1,elmax
elnum(i) = i
*enddo
*do,i,1,elmax-1
*do,j,i+1,elmax
*if,detaf1(j),gt,detaf1(i),then
temp = detaf1(i)
detaf1(i) = detaf1(j)
detaf1(j) = temp
temp = elnum(i)
elnum(i) = elnum(j)
elnum(j)=temp
*endif
*enddo
*enddo
*do,i,1,20
detaf2(i) = detaf1(i) !前20个内力变化最大的单元
elnum2(i) = elnum(i)
*enddo
*do,i,1,20 ! 前20个内力变化最大的单元
numel = elnum2(i)
dfmaxel(0,i) = i
dmmaxel(0,i) = i
*do,j,1,dim
kk = (j-1)*5
dfmaxel(j,0) = kk
dfmaxel(j,i) = ffx(numel,kk)!轴力变化最大单元的轴力
dmmaxel(j,0) = kk
dmmaxel(j,i) = fmz(numel,kk) ! 相应的弯矩
*enddo
*enddo
! 前20个内力最大的单元
*do,i,1,elmax
fabs(i) =abs(fmax(i))
*if,fabs(i),lt,abs(fmin(i)),then
fabs(i) =abs(fmin(i))
*endif
*enddo
*do,i,1,elmax
elnum3(i) =i
*enddo
*do,i,1,elmax-1
*do,j,i+1,elmax
*if,fabs(j),gt,fabs(i),then
temp = fabs(i)
fabs(i) = fabs(j)
fabs(j) =temp
temp= elnum3(i)
elnum3(i) = elnum3(j)
elnum3(j) = temp
*endif
*enddo
*enddo
*do,i,1,20
elnum4(i) = elnum3(i)
nmax(i) = fabs(i)
*enddo
*do,i,1,20 ! 前20个内力最大的单元
numel = elnum4(i)
fmaxel(0,i) = i
mmaxel(0,i) = i
*do,j,1,dim
kk = (j-1)*5
fmaxel(j,0) = kk
fmaxel(j,i) = ffx(numel,kk)!轴力最大单元的轴力
mmaxel(j,0) = kk
mmaxel(j,i) = fmz(numel,kk) ! 相应的弯矩
*enddo
*enddo
save,,,,all
!/title,the 91 node displament vs train position ! 显示图形的名称
!*vplot,diy(1,0),diy(1,1)
!/ui,copy,save,bmp,graph
!/title
!/replot
*do,i,1,30
cc = nodes(i)
/title, y displacement of node %cc% VS. train position
*vplot,disy1(1,0),disy1(1,i)
/ui,copy,save,bmp,graph
*enddo
/title
/sys,rename njq*.bmp aaa*.bmp
*do,i,31,ndnum
cc = nodes(i)
/title, y displacement of node %cc% VS. train position
*vplot,disy1(1,0),disy1(1,i)
/ui,copy,save,bmp,graph
*enddo
/title
/sys,rename njq*.bmp aa*.bmp
!*do,i,1,20
!cc = elnum2(i)
!/title,axis of element %cc% VS. train position
! *vplot,dfmaxel(1,0),dfmaxel(1,i)
!/ui,copy,save,bmp,graph
!/title,moment of element %cc% VS. train position
! *vplot,dmmaxel(1,0),dmmaxel(1,i)
!/ui,copy,save,bmp,graph
!*enddo
!/title
*do,i,1,20
cc = elnum4(i)
/title,axis of element %cc% vs train position
*vplot,fmaxel(1,0),fmaxel(1,i)
/ui,copy,save,bmp,graph
/title,moment of element %cc% vs train position
*vplot,mmaxel(1,0),mmaxel(1,i)
/ui,copy,save,bmp,graph
*enddo
/title
*cfopen,result,txt,,,
*vwrite
(' ')
*vwrite
('**********************南京桥计算结果*****************************')
*vwrite
(' ')
*vwrite
(' ****节点最大位移**** ')
ndnum1 = 5*nint(ndnum/5)
*do,i,1,ndnum1,5
a=nodes(i)
b=nodes(i+1)
c=nodes(i+2)
d=nodes(i+3)
e=nodes(i+4)
*vwrite,a,b,c,d,e
('荷载位置',5(f8.0,5x))
*vwrite,disy1(1,0),disy1(1,i),disy1(1,i+1),disy1(1,i+2),disy1(1,i+3),disy1(
1,i+4)
(f5.0,,5(3x,f10.5))
*enddo
*vwrite
(' ****前20个轴力变化最大的单元和相应的轴力值**** ')
*vwrite,elnum2(1),detaf2(1)
(f15.0,'', f15.1)
*vwrite
(' ')
*do,i,1,18,3
*vwrite
(' ')
a= elnum2(i)
b= elnum2(i+1)
c= elnum2(i+2)
*vwrite,a,b,c
('荷载位置',9x,'单元',f4.0,14x,'单元',f4.0,14x,'单元',f4.0)
*vwrite,dfmaxel(1,0),dfmaxel(1,i),dmmaxel(1,i),dfmaxel(1,i+1),dmmaxel(1,i+1)
,dfmaxel(1,i+2),dmmaxel(1,i+2)
(f5.0,3(f11.1,' ',f11.1))
*enddo
*vwrite
(' ')
a= elnum2(19)
b= elnum2(20)
c= elnum2(20)
*vwrite,a,b,c
('荷载位置',9x,'单元',f4.0,14x,'单元',f4.0,14x,'单元',f4.0)
*vwrite,dfmaxel(1,0),dfmaxel(1,19),dmmaxel(1,19),dfmaxel(1,20),dmmaxel(1,20)
,dfmaxel(1,20),dmmaxel(1,20)
(f5.0,3(f11.1,' ',f11.1))
*vwrite
(' ')
*vwrite
(' ')
*vwrite
(' ***前20个轴力最大的单元和相应的弯矩值*** ')
*vwrite,elnum4(1),detaf2(1)
(f15.0,'', f15.1)
*do,i,1,18,3
*vwrite
(' ')
a= elnum4(i)
b= elnum4(i+1)
c= elnum4(i+2)
*vwrite,a,b,c
('荷载位置',9x,'单元',f4.0,14x,'单元',f4.0,14x,'单元',f4.0)
*vwrite,fmaxel(1,0),fmaxel(1,i),mmaxel(1,i),fmaxel(1,i+1),mmaxel(1,i+1),fmax
el(1,i+2),mmaxel(1,i+2)
(f5.0,3(f11.1,' ',f11.1))
*vwrite
(' ')
*enddo
*vwrite
(' ')
a= elnum4(19)
b= elnum4(20)
c= elnum4(20)
*vwrite,a,b,c
('荷载位置',9x,'单元',f4.0,14x,'单元',f4.0,14x,'单元',f4.0)
*vwrite,fmaxel(1,0),fmaxel(1,19),mmaxel(1,19),fmaxel(1,20),mmaxel(1,20),fmax
el(1,20),mmaxel(1,20)
(f5.0,3(f11.1,' ',f11.1))
*cfclos
回复： 【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
谢谢，我正准备搞一个桥面铺装的动载课题。很有帮助，收藏了！回复： 【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
太感谢回复： 【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
curtain，由于没有车、桥模型，所以无法正常运行。能否把整个命令流给我发一份？谢谢！[ 本帖最后由 77152587 于 2006-10-29 01:25 编辑 ]
回复： 【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
谢谢你，很宝贵，要是能将整个文件共享就好了。回复： 【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
如果没错，这个是水木里的。原帖就没有完全版，它只是提供了与用户互动的APDL怎么操作（如用户可以随意改变参数），以及过程是什么样的。建模要自己来。回复： 【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
cswbww,确实是你说的这样的.不过似乎建模本身并不是大家很怵的事情,最简单的可以把sap2000搬来,甚至可以用apdl直接将建模的界面写出来,关键是制定一下桥的类型就可以了.谢谢大家.
回复： 【转帖】一个火车过桥动态加载的例子（但愿以前没人贴过）
不错不错