FLAC2.0依次得到安全系数1.46 0.33 1.84 0.87 这样的结果合理吗？

lxg20054193

我在计算分四步开挖边坡的模型算安全系数的时候，依次得到安全系数1.46 0.33 1.84 0.87  这样的结果合理吗？
请高手们指教下
config
grid 16,16
gen (0.0,0.0) (0.0,8.0) (20.0,8.0) (20.0,0.0) i 1 9 j 1 9
gen (0.0,8.0) (0.0,16.0) (36.0,16.0) (20.0,8.0) i 1 9 j 9 17
gen (20.0,0.0) (20.0,8.0) (56.0,8.0) (56.0,0.0) i 9 17 j 1 9
gen (20.0,8.0) (36.0,16.0) (56.0,16.0) (56.0,8.0) i 9 17 j 9 17
model mohr i=1,16 j=1,16
mark j 16
mark j 14
mark j 11
mark j 9
group 'User:4' region 15 9
model mohr group 'User:4'
prop density=2140.0 bulk=1.69048E7 shear=8.25581E6 cohesion=31.2 friction=24.0 dilation=0.0 tension=0.0 group 'User:4'
group 'User:4' region 15 6
model mohr group 'User:4'
prop density=2140.0 bulk=1.69048E7 shear=8.25581E6 cohesion=31.2 friction=24.0 dilation=0.0 tension=0.0 group 'User:4'
group 'User:3' region 16 12
model mohr group 'User:3'
prop density=2030.0 bulk=1.75439E7 shear=7.63359E6 cohesion=21.3 friction=20.6 dilation=0.0 tension=0.0 group 'User:3'
group 'User:2' region 16 15
model mohr group 'User:2'
prop density=1980.0 bulk=5.7971E6 shear=3.14961E6 cohesion=15.5 friction=18.5 dilation=0.0 tension=0.0 group 'User:2'
group 'User:1' region 15 16
model mohr group 'User:1'
prop density=1860.0 bulk=8.33333E6 shear=4.29688E6 cohesion=14.0 friction=17.8 dilation=0.0 tension=0.0 group 'User:1'
fix  x i 1
fix  x i 17
fix  x y j 1
history 1 xdisp i=9, j=17
history 2 ydisp i=9, j=17
set gravity=9.81


history 999 unbalanced
solve elastic

tong2005

没有进行开挖，得不到您讲的结论。

tong2005

flac2.0没有这项计算功能。估计为4.0以上版本。