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发表于 2004-2-21 17:42:41
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来自 广东广州
回复: 【注意】请教可不可以用ls-dyna算流固耦合,而前处理软件是ansys吗?
其实我是先用femb熟悉模拟流固耦合问题的操作过程,这主要还是我不太了解其中的参数设置,而femb用起来比较方便。等熟悉后然后再准备用ansys建模,不过用ansys比较麻烦。如果能用其它的最好不要用ansys。最后还想问问htbbzzg网站顾问和ls_dyna一个问题:你们能这个message文件看出什么问题?请其他高手也帮忙解决一下。message文件如下:
Date: 02/21/2004 Time: 17:06:43
___________________________________________________
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| Livermore Software Technology Corporation |
| |
| 7374 Las Positas Road |
| Livermore, CA 94550 |
| Tel: (925) 449-2500 Fax: (925) 449-2507 |
| www.lstc.com |
|_________________________________________________|
| |
| LS-DYNA, A Program for Nonlinear Dynamic |
| Analysis of Structures in Three Dimensions |
| Version: 960 Date: 07/26/2002 |
| Revision: 1488 Time: 17:41:49 |
| |
| Features enabled in this version: |
| ANSYS Database format |
| Shared Memory Parallel |
| |
| Licensed to: |
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| Platform : PC (Intel) |
| OS Level : WINDOWS 2000 |
| Hostname :|
| Precision : Single precision (I4R4) |
| |
| Unauthorized use infringes LSTC copyrights |
|_________________________________________________|
Input file: F:\ANSYSD~1\FEMBFI~1\INPUTD~1.DYN
expanding memory to 41943040
******** notice ******** notice ******** notice ********
* *
* This is the LS-DYNA Explicit Finite Element code. *
* Neither LSTC nor the authors assume any responsibility for *
* the validity, accuracy, or applicability of any results *
* obtained from this system. The user must verify his own *
* results. *
* *
* LSTC endeavors to make the LS-DYNA code as complete, *
* accurate and easy to use as possible. *
* Suggestions and comments are welcomed. Please report any *
* errors encountered in either the documentation or results *
* immediately to LSTC through your site focus. *
* *
* Copyright (C) 1990-2002 *
* by Livermore Software Technology Corp. (LSTC) *
* All rights reserved *
* *
******** notice ******** notice ******** notice ********
contracting memory to 55384
expanding memory to 90768
expanding memory to 147792
expanding memory to 214032
expanding memory to 359504
expanding memory to 420515
expanding memory to 451015
expanding memory to 471632
expanding memory to 572583
expanding memory to 593499
expanding memory to 658645
contracting memory to 2
LS-DYNA will perform a structural only analysis
LS-DYNA user input
ls-dyna (version 960 ) date 07/26/2002
expanding memory to 2961
expanding memory to 21841
expanding memory to 66849
expanding memory to 550861
expanding memory to 557047
contracting memory to 553501
expanding memory to 712827
expanding memory to 714848
expanding memory to 721708
expanding memory to 736600
expanding memory to 739718
expanding memory to 787765
expanding memory to 813277
expanding memory to 1240170
expanding memory to 1354323
expanding memory to 1399313
expanding memory to 1458023
expanding memory to 1879834
expanding memory to 1905789
expanding memory to 1935750
expanding memory to 2067027
contracting memory to 2067027
contracting memory to 2067027
expanding memory to 2067107
expanding memory to 2092619
contracting memory to 2092619
expanding memory to 2092737
expanding memory to 2092741
expanding memory to 2163473
E r r o r t e r m i n a t i o n
Memory required for explicit solution: 2163473
Additional dynamically allocated memory: 0
Total: 2163473
T i m i n g i n f o r m a t i o n
CPU(seconds) %CPU Clock(seconds) %Clock
----------------------------------------------------------------
Initialization ....... 0.0000E+00 0.00 0.0000E+00 0.00
Element processing ... 0.0000E+00 0.00 0.0000E+00 0.00
Binary databases ..... 0.0000E+00 0.00 0.0000E+00 0.00
ASCII database ....... 0.0000E+00 0.00 0.0000E+00 0.00
Contact algorithm .... 0.0000E+00 0.00 0.0000E+00 0.00
Contact entities ..... 0.0000E+00 0.00 0.0000E+00 0.00
Rigid bodies ......... 0.0000E+00 0.00 0.0000E+00 0.00
Implicit Nonlinear ... 0.0000E+00 0.00 0.0000E+00 0.00
Implicit Lin. Alg. ... 0.0000E+00 0.00 0.0000E+00 0.00
----------------------------------------------------------------
T o t a l s 0.0000E+00 0.00 0.0000E+00 0.00
Problem time = 0.0000E+00
Problem cycle = 0
Total CPU time = 0 seconds ( 0 hours 0 minutes 0 seconds)
CPU time per zone cycle = 0 nanoseconds
Clock time per zone cycle= 0 nanoseconds
Number of CPU's 1
Start time 02/21/2004 17:06:43
End time 02/21/2004 17:06:46
Elapsed time 3 seconds ( 0 hours 0 minutes 3 seconds)
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