pinkfloyd007 发表于 2006-5-27 22:27:56

Help!我的一个热力瞬态分析不成功,请指点!

此命令要模拟一个燃烧炉,是厚壁圆筒,内层砖砌体厚370mm,外层混凝土厚100mm,外直径2.14m,内直径1.2m,炉内温200℃,炉外温-10℃,取一个横截面实体,实体厚度(z向)为0.05m,想用ansys9.0作热力耦合瞬态分析,急用却调试不成功,另外混凝土比热取为882j/kg.k不知是否正确,请各位达人指点迷津,不胜感激!qq 94642494

/prep7
et,1,solid5
mp,kxx,1,0.8
mp,ex,1,2.7e9
mp,nuxy,1,.25
mp,alpx,1,5.6e-6
mp,dens,1,1800
mp,c,1,800
mp,kxx,2,1.4
mp,ex,2,3e10
mp,nuxy,2,.15
mp,alpx,2,10e-6
mp,dens,2,2380
mp,c,2,882
csys,1
cylind,0.6,0.97,0,0.05,0,45
cylind,0.97,1.07,0,0.05,0,45
vglue,all
numcmp,volu
vsel,s,volu,,1
vatt,1,1,1
vsel,s,volu,,2
vatt,2,1,1
vsel,all
lsel,s,length,,0.05
lesize,all,,,2
lsel,s,length,,1
lesize,all,,,5
lsel,s,loc,x,0.6
lsel,a,loc,x,0.97
lsel,a,loc,x,1.07
lsel,u,length,,0.05
lesize,all,,,5
mshk,1
msha,0,3d
vmesh,all
nsel,s,loc,y,0
nsel,a,loc,y,45
dsym,symm,y,1    *对称约束
nsel,s,loc,z      
dsym,symm,z,1   
nsel,s,loc,z,0.05
cp,1,uz,all
nsel,s,loc,x,1.07
d,all,temp,200
nsel,all
finish
/solu
antype,trans
timint,off,struc
cnvtol,heat
cnvtol,f
autots,on
outres,,all
kbc,0
tref,-10
tunif,-10
deltim,1,,60
time,210
solve
finish
/post1
plnsol,temp *画节点结果为连续的轮廓线
/expand,8,polar,half,,45
plesol,s,eqv*图表元素的等效应力
/expand
/replot
finish
/post26
nsol,2,48,temp,,inner
nsol,3,139,temp,,outer
add,4,3,2,,delta,,,1,-1
/grid,1
/axlab,y,temp
plvar,2,3,4
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