摩云 发表于 2006-8-28 11:20:57

瞬态热分析遇到的问题

瞬态热计算到第二个荷载步出现如下错误信息,不知如何解决。
*** ERROR ***
Present time 3600 is less than or equal to the previous time in a      
transient analysis.

附命令流如下,请各位高手帮助
/SOLU
Time,3600   
timint,on
DELTIM,10,1,100
AUTOTS,on 
OUTRES,ALL,ALL 
KBC,0
*do,i,1,24,1
t=i   
DDELET,ALL,TEMP   
FLST,2,12,4,ORDE,12
FITEM,2,14
FITEM,2,-15
FITEM,2,17
FITEM,2,-18
FITEM,2,28
FITEM,2,43
FITEM,2,48
FITEM,2,51
FITEM,2,54
FITEM,2,66
FITEM,2,104
FITEM,2,111
SFL,P51X,CONV,3.5, ,Ta,
FLST,2,30,4,ORDE,25
FITEM,2,2   
FITEM,2,6   
FITEM,2,10
FITEM,2,12
FITEM,2,-13
FITEM,2,25
FITEM,2,29
FITEM,2,32
FITEM,2,37
FITEM,2,40
FITEM,2,45
FITEM,2,-46
FITEM,2,50
FITEM,2,55
FITEM,2,-56
FITEM,2,58
FITEM,2,-60
FITEM,2,62
FITEM,2,-64
FITEM,2,67
FITEM,2,-71
FITEM,2,82
FITEM,2,83
FITEM,2,106
FITEM,2,110
DL,P51X, ,TEMP,Ta,0
LSWRITE,t   
*enddo 
LSSOLVE,1,24,1,
FINISH

cjianhf8488 发表于 2006-9-1 11:28:48

在瞬态热分析中,后一载荷步的结束时间必须大于前一个载荷步的结束时间!
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