快速升温,保温后后,快速降温,怎么做?
一个工件,材料为泥土,工件从25摄氏度经过2个小时升至1000摄氏度,保温8小时,然后经过2个小时冷却至25摄氏度,要求计算工件最终冷却至25摄氏度后的变形!
能否就上述分析要求描述一下分析过程(使用ansys软件分析计算),需求哪些材料参数? 工件模型为不规则的几何体即可,关键是分析过程! 一些关键步骤
tref,25
tunif,25
kbc,0
time,2*3600
d,all,temp,1000
solve
kbc,1
time,(2+8)*3600
solve
kbc,0
time,(2+8+2)*3600
d,all,temp,25
solve 谢谢啊,我再看看。。。 /PREP7
!*ET,1,SOLID87
ET,1,SOLID98
!*
!*
MPTEMP,,,,,,,,
MPTEMP,1,0
MPDATA,EX,1,,2e11
MPDATA,PRXY,1,,0.3
MPTEMP,,,,,,,,
MPTEMP,1,0
MPDATA,DENS,1,,7800
MPTEMP,,,,,,,,
MPTEMP,1,0
UIMP,1,REFT,,,
MPDATA,ALPX,1,,1.23e-5
MPTEMP,,,,,,,,
MPTEMP,1,0
MPDATA,KXX,1,,70
MPTEMP,,,,,,,,
MPTEMP,1,0
MPDATA,C,1,,450
BLOCK,,1,,1,,0.1,
/VIEW,1,1,1,1
/ANG,1
/REP,FAST
SMRT,6
SMRT,5
SMRT,4
MSHAPE,1,3D
MSHKEY,0
!*
CM,_Y,VOLU
VSEL, , , , 1
CM,_Y1,VOLU
CHKMSH,'VOLU'
CMSEL,S,_Y
!*
VMESH,_Y1
!*
CMDELE,_Y
CMDELE,_Y1
CMDELE,_Y2
!*
FINISH
/SOL
!*
ANTYPE,4
!*
TRNOPT,FULL
LUMPM,1
!*
tref,25
tunif,25
kbc,0
time,1e-3
d,all,temp,25
solve
kbc,0
time,2*3600
d,all,temp,1000
solve
kbc,1
time,(2+8)*3600
solve
kbc,0
time,(2+8+2)*3600
d,all,temp,25
solve
!*
NSOL,2,384,TEMP, ,jnz
!*
PLVAR,jnz, , , , , , , , , , 感谢!!!非常感谢 非常感谢!!!!!!!:handshake
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