pie函数求助
我用h=pie(x,y,str)的函数形式画了饼图，str是字符串向量，如str=['石英充填:' '23%']的形式;，现在要改变str字符显示的文字大小，我用set(h,'FontSize',8)提示错误，请问是什么问题，怎么解决？ 1# iryouott给你一个例子：
clear;clc;close all
h = pie(1:3,{'Taxes','Expenses','Profit'});
arrayfun(@(x)set(h(x),'FontSize',x*10),2:2:6);
在图形界面用鼠标修改吧,也许还方便点.或者在
function hh = pie(varargin)
%PIE Pie chart.
% PIE(X) draws a pie plot of the data in the vector X.The values in X
% are normalized via X/SUM(X) to determine the area of each slice of pie.
% If SUM(X) <= 1.0, the values in X directly specify the area of the pie
% slices.Only a partial pie will be drawn if SUM(X) < 1.
%
% PIE(X,EXPLODE) is used to specify slices that should be pulled out from
% the pie.The vector EXPLODE must be the same size as X. The slices
% where EXPLODE is non-zero will be pulled out.
%
% PIE(...,LABELS) is used to label each pie slice with cell array LABELS.
% LABELS must be the same size as X and can only contain strings.
%
% PIE(AX,...) plots into AX instead of GCA.
%
% H = PIE(...) returns a vector containing patch and text handles.
%
% Example
% pie(,{'North','South','East','West'})
%
% See also PIE3.
% Clay M. Thompson 3-3-94
% Copyright 1984-2004 The MathWorks, Inc.
% $Revision: 1.16.4.6 $$Date: 2004/04/10 23:31:59 $
% Parse possible Axes input
= axescheck(varargin{:});
if nargs==0, error('Not enough input arguments.'); end
x = args{1}(:); % Make sure it is a vector
args = args(2:end);
if nargs>3, error('Too many input arguments.'); end
nonpositive = (x <= 0);
if any(nonpositive)
warning('MATLAB:pie:NonPositiveData',...
'Ignoring non-positive data in pie chart.');
x(nonpositive) = [];
end
xsum = sum(x);
if xsum > 1+sqrt(eps), x = x/xsum; end
% Look for labels
if nargs>1 & iscell(args{end})
txtlabels = args{end};
if any(nonpositive)
txtlabels(nonpositive) = [];
end
args(end) = [];
else
for i=1:length(x)
if x(i)<.01,
txtlabels{i} = '< 1%';
else
txtlabels{i} = sprintf('%d%%',round(x(i)*100));
end
end
end
% Look for explode
if isempty(args),
explode = zeros(size(x));
else
explode = args{1};
if any(nonpositive)
explode(nonpositive) = [];
end
end
explode = explode(:); % Make sure it is a vector
if length(txtlabels)~=0 & length(x)~=length(txtlabels),
error('Cell array of strings must be the same length as X.');
end
if length(x) ~= length(explode),
error('X and EXPLODE must be the same length.');
end
cax = newplot(cax);
next = lower(get(cax,'NextPlot'));
hold_state = ishold(cax);
theta0 = pi/2;
maxpts = 100;
inside = 0;
h = [];
for i=1:length(x)
n = max(1,ceil(maxpts*x(i)));
r = ;
theta = theta0 + *2*pi;
if inside,
= pol2cart(theta0 + x(i)*pi,.5);
else
= pol2cart(theta0 + x(i)*pi,1.2);
end
= pol2cart(theta,r);
if explode(i),
= pol2cart(theta0 + x(i)*pi,.1);
xtext = xtext + xexplode;
ytext = ytext + yexplode;
xx = xx + xexplode;
yy = yy + yexplode;
end
theta0 = max(theta);
h = [h,patch('XData',xx,'YData',yy,'CData',i*ones(size(xx)), ...
'FaceColor','Flat','parent',cax), ...
text(xtext,ytext,txtlabels{i},...
'HorizontalAlignment','center','parent',cax)];
end
if ~hold_state,
view(cax,2); set(cax,'NextPlot',next);
axis(cax,'equal','off',[-1.2 1.2 -1.2 1.2])
end
if nargout>0, hh = h; end
% Register handles with m-code generator
if ~isempty(h)
mcoderegister('Handles',h,'Target',h(1),'Name','pie');
end
这个matlab的pie函数中的
h = [h,patch('XData',xx,'YData',yy,'CData',i*ones(size(xx)), ...
'FaceColor','Flat','parent',cax), ...
text(xtext,ytext,txtlabels{i},...
'HorizontalAlignment','center','parent',cax)];
的text段改写成
text(xtext,ytext,txtlabels{i},...
'HorizontalAlignment','center','parent',cax),'FontSize',15;
15为数字大小,具体按你自己的要求改动.颜色也可以类似舔加. 好的，谢谢两位的指点
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