关于精度(矩阵)
s =1.7519 0 0 0 0 0 0 0 0 0
0 0.3429 0 0 0 0 0 0 0 0
0 0 0.0357 0 0 0 0 0 0 0
0 0 0 0.0025 0 0 0 0 0 0
0 0 0 0 0.0001 0 0 0 0 0
0 0 0 0 0 0.0000 0 0 0 0
0 0 0 0 0 0 0.0000 0 0 0
0 0 0 0 0 0 0 0.0000 0 0
0 0 0 0 0 0 0 0 0.0000 0
0 0 0 0 0 0 0 0 0 0.0000
实际上这些对角线上的数值不是0,而是
s(1,1)=1.7519
s(2,2)= 0.3429
s(3,3)=0.0357
s(4,4) = 0.0025
s(5,5) =1.2875e-004
s(6,6)=4.7297e-006
s(7,7) =1.2290e-007
s(8,8) =2.1474e-009
s(9,9) =2.2667e-011
s(10,10) =1.0933e-013
我想知道一下:怎么样把这些实际的值还是显示原值而不显示近似值?谢谢 已经解决谢谢~~
format short eng 就OK了~~
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