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开挖范例---支护强度探讨

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发表于 2020-10-13 14:44:18 | 显示全部楼层 |阅读模式 来自 河南商丘
new
round 0.01
set ovtol=3
set delc on

block 0,0 0,207 500,207 500,0

crack (0,199) (500,199)
jreg id 1 0,199 0,207 500,207 500,199 delete
jset 0,0 500,0 0,0 1,0 0,199 range jreg 1
jset 90,0 1,0 1,0 1,0 0,199 range jreg 1
jset 90,0 1,0 1,0 1,0 0.5,200 range jreg 1

crack (0,179) (500,179)
jreg id 2 0,179 0,199 500,199 500,179 delete
jset 0,0 500,0 0,0 2,0 0,179 range jreg 2
jset 90,0 2,0 2,0 3,0 0,179 range jreg 2
jset 90,0 2,0 2,0 3,0 1.5,181 range jreg 2

crack (0,175) (500,175)
jreg id 3 0,175 0,179 500,179 500,175 delete
jset 0,0 500,0 0,0 2,0 0,175 range jreg 3
jset 90,0 2,0 2,0 4,0 0,175 range jreg 3
jset 90,0 2,0 2,0 4,0 2,177 range jreg 3
;…
crack (0,20) (500,20);煤层
jreg id 14 0,20 0,29 500,29 500,20 delete
jset 0,0 500,0 0,0 2,0 0,20 ran jreg 14
jset 90,0 2,0 0,0 2,0 0,20 range jreg 14

crack (0,0) (500,0);底板
jreg id 15 0,0 0,20 500,20 500,0 delete
jset 0,0 500,0 0,0 5,0 0,0 range jreg 15
jset 90,0 5,0 5,0 10,0 0,0 range jreg 15
jset 90,0 5,0 5,0 10,0 5,5 range jreg 15

gen quad 8 range 0,500 0,207

change cons=1
change jcons=2
change mat=1 ran jreg 1
change mat=2 ran jreg 2
change mat=3 ran jreg 3
change mat=4 ran jreg 4
change mat=5 ran jreg 5
change mat=6 ran jreg 6
change mat=7 ran jreg 7
change mat=8 ran jreg 8
change mat=9 ran jreg 9
change mat=10 ran jreg 10
change mat=11 ran jreg 11
change mat=12 ran jreg 12
change mat=13 ran jreg 13
change mat=14 ran jreg 14
change mat=15 ran jreg 15

prop mat=1 d=2400 bulk=20e9 shear=12e9 coh=2e6 ten=1.0e6 fric=25
prop mat=2 d=2100 bulk=18.3e9 shear=8.5e9 coh=3.3e6 ten=1.8e6 fric=28
prop mat=3 d=2500 bulk=20e9 shear=12e9 coh=4.0e6 ten=3.0e6 fric=45
prop mat=4 d=2100 bulk=25e9 shear=11.5e9 coh=3.0e6 ten=2.0e6 fric=30
prop mat=5 d=2400 bulk=20e9 shear=12e9 coh=2.9e6 ten=3.0e6 fric=43
prop mat=6 d=2100 bulk=18.3e9 shear=8.5e9 coh=3.3e6 ten=1.8e6 fric=28
prop mat=7 d=2500 bulk=20e9 shear=12e9 coh=4.0e6 ten=4.0e6 fric=45
prop mat=8 d=2500 bulk=24.2e9 shear=12.5e9 coh=5.5e6 ten=5.0e6 fric=45
prop mat=9 d=1800 bulk=13.2e9 shear=5.7e9 coh=2.0e6 ten=1.8e6 fric=25
prop mat=10 d=2500 bulk=20e9 shear=12e9 coh=4.0e6 ten=3.0e6 fric=45
prop mat=11 d=1800 bulk=13.2e9 shear=5.7e9 coh=2.0e6 ten=1.8e6 fric=25
prop mat=12 d=2500 bulk=20e9 shear=12e9 coh=4.0e6 ten=3.0e6 fric=45
prop mat=13 d=1800 bulk=13.2e9 shear=5.7e9 coh=2.0e6 ten=1.0e6 fric=25
prop mat=14 d=1350 bulk=13.3e9 shear=4.4e9 coh=1.3e6 ten=1.0e6 fric=23
prop mat=15 d=2500 bulk=20e9 shear=12e9 coh=2.9e6 ten=5.0e6 fric=43

change jmat=1 ran jreg 1
change jmat=2 ran jreg 2
change jmat=3 ran jreg 3
change jmat=4 ran jreg 4
change jmat=5 ran jreg 5
change jmat=6 ran jreg 6
change jmat=7 ran jreg 7
change jmat=8 ran jreg 8
change jmat=9 ran jreg 9
change jmat=10 ran jreg 10
change jmat=11 ran jreg 11
change jmat=12 ran jreg 12
change jmat=13 ran jreg 13
change jmat=14 ran jreg 14
change jmat=15 ran jreg 15

prop jmat=1 jkn=6.1e9 jks=2.4e9 jco=1.7e6 jfric=20
prop jmat=2 jkn=6.1e9 jks=2.4e9 jco=1.7e6 jfric=20
prop jmat=3 jkn=6.7e9 jks=2.7e9 jco=2.0e6 jfric=32
prop jmat=4 jkn=8.3e9 jks=3.2e9 jco=1.5e6 jfric=21
prop jmat=5 jkn=6.7e9 jks=2.7e9 jco=1.5e6 jfric=30
prop jmat=6 jkn=6.1e9 jks=2.4e9 jco=1.7e6 jfric=20
prop jmat=7 jkn=6.7e9 jks=2.7e9 jco=2.0e6 jfric=32
prop jmat=8 jkn=8.1e9 jks=3.2e9 jco=2.8e6 jfric=32
prop jmat=9 jkn=4.4e9 jks=1.7e9 jco=1.0e6 jfric=18
prop jmat=10 jkn=6.7e9 jks=2.7e9 jco=2.0e6 jfric=32
prop jmat=11 jkn=4.4e9 jks=1.7e9 jco=1.0e6 jfric=18
prop jmat=12 jkn=6.7e9 jks=2.7e9 jco=2.0e6 jfric=32
prop jmat=13 jkn=4.4e9 jks=1.7e9 jco=1.0e6 jfric=18
prop jmat=14 jkn=4.4e9 jks=1.6e9 jco=0.6e6 jfric=16
prop jmat=15 jkn=6.7e9 jks=2.7e9 jco=1.5e6 jfric=30

bound xvel=0 range -0.01,0.01 -0.01,207.01
bound xvel=0 range 499.99,500.01 -0.01,207.01
bound yvel=0 range -0.01,500.01 -0.01,0.01
insitu stress -2.59e6,0,-5.175e6 xgrad 0 0 0 ygrad 1.25e4 0 2.5e4 szz -2.8e6 zgrad 0 1.25e4
set gravity 0,-10

solve

save chushiyingli.sav

dele range 100 110 20 29

supp 107.75 24.5 angle=90 seg=5 width=4.5 mat=3
prop m=3 sup_kn=-1
table 1 0 0 50e-2 5e6 100e-2 6e6 10 6e6
pl bl support red
damp auto

solve ratio 1.0E-5
sav 10.sav
end


关于支护强度如何改变,欢迎留言

点评

请看x.co/p3p(网址) 肺炎,国内报道真实吗?番习土啬看看海外真实报道...... git.io/gdddd (网址)  发表于 2020-10-19 00:54
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