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- 2005-7-21
- 仿真币
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我得到了整体刚度矩阵,可是不知道要怎么看.
帮助里面说的含义如下:
The assembled sparse matrix operator data are written to the text file as a series of comma-separated lists. Each row in the file represents a single matrix entry; a row is written as a comma-separated list with the following elements: - Row node label
- Degree of freedom for row node
- Column node label
- Degree of freedom for column node
- Matrix entry
得到的结果截取一部分如下:
1,1,1,1,1.262499989749938e-001
1,2,1,2,1.262499989749938e-001
1,3,1,3,1.262499989749938e-001
2,1,2,1,2.524999979499878e-001
2,2,2,2,2.524999979499878e-001
2,3,2,3,2.524999979499878e-001
3,1,3,1,2.525000168874888e-001
3,2,3,2,2.525000168874888e-001
3,3,3,3,2.525000168874888e-001
4,1,4,1,2.525000269874892e-001
4,2,4,2,2.525000269874892e-001
4,3,4,3,2.525000269874892e-001
5,1,5,1,2.525000168874888e-001
5,2,5,2,2.525000168874888e-001
5,3,5,3,2.525000168874888e-001
......
请问怎么样看这些数据,要怎么排列得到整体刚度矩阵?
请牛人帮帮忙看一下,麻烦啦~~~ |
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