请教，一求解就死机或者自动退出

junnerf

要对两个黏在一起的体进行热瞬态分析，和结构分析。下面的体温度恒定，看对上面的体中间的一个衡梁的影响
命令行如下
/FILENAME,PiezoTransducer
/TITLE,Struct-Thermal Analysis
/UNITS,SI          !国际单位制
*set,length,0.17e-3 !定义梁的长度
*set,width,0.04e-3 !定义梁的宽度
!定义各层距底面的厚度
*set,thickness1,0.45e-3 !Layer 1
*set,thickness2,0.44e-3 !Layer 2
*set,thickness3,0.43e-3 !Layer 3
*set,thickness4,0.39e-3 !Layer 4
*set,thickness5,0.10e-3 !Layer 5

/PREP7
ET,1,SOLID90
KEYOPT,1,1,1
DOF,UX,UY,UZ
MP,DENS,1,2330  !定义材料1（Si）的材料属性：密度
MP,EX,1,130E9  !弹性模量
MP,C,1,700  !比热
MP,PRXY,1,0.278  !泊松比
MP,ALPX,1,2.6E-6 !线膨胀系数
MP,KXX,1,148  !热传导率
MP,DENS,2,7850  !定义材料2（Cu）的材料属性
MP,EX,2,105E9
MP,C,2,386
MP,PRXY,2,0.31
MP,ALPX,2,17.5E-6
MP,KXX,2,398
!创建几何模型
BLOCK,0.5e-3,-0.5e-3,0.5e-3,-0.5e-3,0,0.45e-3    !Volume1

!Keypoints in Layer 1(Volume1 includes 8 Kpts)
k,9,-0.245e-3,length/2,thickness1
k,10,-0.245e-3,0.104e-3,thickness1
K,11,,0.245e-3,thickness1
k,12,0.245e-3,0.104e-3,thickness1
k,13,0.245e-3,-0.104e-3,thickness1
k,14,,-0.245e-3,thickness1
k,15,-0.245e-3,-0.104e-3,thickness1
k,16,-0.245e-3,-length/2,thickness1
k,17,-0.245e-3-width,-length/2,thickness1
k,18,-0.245e-3-width,-0.104e-3-width*0.577,thickness1
k,19,,-0.245e-3-width*1.155,thickness1
k,20,0.245e-3+width,-0.104e-3-width*0.577,thickness1
k,21,0.245e-3+width,0.104e-3+width*0.577,thickness1
k,22,,0.245e-3+width*1.155,thickness1
k,23,-0.245e-3-width,0.104e-3+width*0.577,thickness1
k,24,-0.245e-3-width,length/2,thickness1
!Keypoints in Layer 4
k,25,-0.245e-3,length/2,thickness4
k,26,-0.245e-3,0.104e-3,thickness4
K,27,,0.245e-3,thickness4
k,28,0.245e-3,0.104e-3,thickness4
k,29,0.245e-3,-0.104e-3,thickness4
k,30,,-0.245e-3,thickness4
k,31,-0.245e-3,-0.104e-3,thickness4
k,32,-0.245e-3,-length/2,thickness4
k,33,-0.245e-3-width,-length/2,thickness4
k,34,-0.245e-3-width,length/2,thickness4
!Keypoints in Layer 5
k,35,-0.245e-3-width,-0.104e-3-width*0.577,thickness5
k,36,,-0.245e-3-width*1.155,thickness5
k,37,0.245e-3+width,-0.104e-3-width*0.577,thickness5
k,38,0.245e-3+width,0.104e-3+width*0.577,thickness5
k,39,,0.245e-3+width*1.155,thickness5
k,40,-0.245e-3-width,0.104e-3+width*0.577,thickness5

!Keypoints in Layer 2
k,41,-0.175e-3,0.028e-3,thickness2
k,42,,0.13e-3,thickness2
k,43,0.175e-3,0.028e-3,thickness2
k,44,0.175e-3,-0.028e-3,thickness2
k,45,,-0.13e-3,thickness2
k,46,-0.175e-3,-0.028e-3,thickness2

!Keypoints in Layer 3
k,47,-0.175e-3,0.028e-3,thickness3
k,48,,0.13e-3,thickness3
k,49,0.175e-3,0.028e-3,thickness3
k,50,0.175e-3,-0.028e-3,thickness3
k,51,,-0.13e-3,thickness3
k,52,-0.175e-3,-0.028e-3,thickness3

V,41,42,45,46,47,48,51,52 !Volume 2
V,42,43,44,45,48,49,50,51 !Volume 3
VADD,2,3   !Volume 4,即空腔
V,10,11,14,15,26,27,30,31 !Volume 2
V,11,12,13,14,27,28,29,30 !Volume 3
VADD,2,3   !Volume 5
VSBV,5,4   !Volume 2
V,24,9,16,17,34,25,32,33 !Volume 3,即梁
VADD,2,3   !Volume 4
V,23,22,19,18,40,39,36,35 !Volume 2
V,22,21,20,19,39,38,37,36 !Volume 3
VADD,2,3   !Volume 5
VSBV,1,5   !Volume 2
VADD,2,4   !Volume 1,即所需的上体

BLOCK,0.5e-3,-0.5e-3,0.5e-3,-0.5e-3,0,-0.4e-3    !Volume2
VGLUE,1,2   !下面的体编号变成了3，不知道为什么
VSEL,S,,,3
VATT,2,,1,0
VSEL,S,,,1
VATT,1,,1,0
VSEL,A,,,3
VPLOT,1,3
VSEL,s,,,1,3
SMRTSIZE,4
mshkey,0  !自由网格
mshape,1,3D  !三角网格
VMESH,ALL
FINISH
/SOL
ANTYPE,4
TRNOPT,FULL
LUMPM,0
!给底面增加位移限制
DA,22,,UX,0
DA,22,,UY,0
DA,22,,UZ,0
!底座温度限制为100
VSEL,S,,,3
BFV,ALL,TEMP,100
!上面主体初始温度
VSEL,S,,,1
NSLV,S,0
IC,ALL,TEMP,25
!设置分析选项
TIME,300
AUTOTS,-1
DELTIM,10,2,20,1
KBC,0   !Stepped
OUTRES,ALL,ALL
SOLVE
FINISH

前面的材料属性是查到的，后面的载荷施加我觉得应该没什么问题啊，由于是新手，分析选项是按照书上的一个例子来设置的，前面都可以运行，建立模型，划分网格，施加约束，可是到了最后一求解就死机了，有时候就自动退出。是在想不出是哪里的问题，请高手赐教。

senja

到工作路径下找到.err文件，记事本打开看看有什么提示。
这种情况可能是错误、警告过多导致的。在错误文件中查看具体信息