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本帖最后由 cloud328 于 2010-4-2 20:52 编辑
1.我的第一个问题:
今天后来仔细检查了下我FLAC数据文件,原来是有些节点不对应,后来改了下,但有点问题我不知道还能不能继续算
gen zone cshell p0 0 0 0 p1 8.7 0 0 p2 0 40 0 p3 0 0 8.7 p4 8.7 40 0 p5 0 40 8.7 p8 5.2 0 0 p9 0 0 5.2 p10 5.2 40 0 p11 0 40 5.2 size 5 20 9 ;
gen zon cshell p0 0 0 0 p1 5.2 0 0 p2 0 40 0 p3 0 0 5.2 p4 5.2 40 0 p5 0 40 5.2 p8 4.85 0 0 p9 0 0 4.85 p10 4.85 40 0 p11 0 40 4.85 size 1 20 9 group rock1 ;
gen zon cshell p0 0 0 0 p1 4.85 0 0 p2 0 40 0 p3 0 0 4.85 p4 4.85 40 0 p5 0 40 4.85 p8 4.5 0 0 p9 0 0 4.5 p10 4.5 40 0 p11 0 40 4.5 size 1 20 9 group rock2 ;
gen zon cshell p0 0 0 0 p1 4.200223 0 -2.425 p2 0 40 0 p3 4.85 0 0 p4 4.200223 40 -2.425 p5 4.85 40 0 p8 3.897114 0 -2.25 p9 4.5 0 0 p10 3.897114 40 -2.25 p11 4.5 40 0 size 1 20 3 group rock2 ;
gen zon cshell p0 0 0 0 p1 4.503332 0 -2.600 p2 0 40 0 p3 5.20 0 0 p4 4.503332 40 -2.600 p5 5.20 40 0 p8 4.200223 0 -2.425 p9 4.85 0 0 p10 4.200223 40 -2.425 p11 4.85 40 0 size 1 20 3 group rock1 ;
gen zon cshell p0 0 0 0 p1 7.534421 0 -4.350 p2 0 40 0 p3 8.70 0 0 p4 7.534421 40 -4.350 p5 8.70 40 0 p8 4.503332 0 -2.600 p9 5.20 0 0 p10 4.503332 40 -2.600 p11 5.20 40 0 size 5 20 3 ;
gen zon cshell p0 0 0 0 p1 0 0 -3.550 p2 0 40 0 p3 4.200223 0 -2.425 p4 0 40 -3.550 p5 4.200223 40 -2.425 p8 0 0 -3.200 p9 3.897114 0 -2.25 p10 0 40 -3.200 p11 3.897114 40 -2.25 size 1 20 6 group rock2 ;
gen zon cshell p0 0 0 0 p1 0 0 -3.900 p2 0 40 0 p3 4.503332 0 -2.600 p4 0 40 -3.900 p5 4.503332 40 -2.600 p8 0 0 -3.550 p9 4.200223 0 -2.425 p10 0 40 -3.550 p11 4.200223 40 -2.425 size 1 20 6 group rock1;
gen zon cshell p0 0 0 0 p1 0 0 -7.400 p2 0 40 0 p3 7.534421 0 -4.350 p4 0 40 -7.400 p5 7.534421 40 -4.350 p8 0 0 -3.900 p9 4.503332 0 -2.600 p10 0 40 -3.900 p11 4.503332 40 -2.600 size 5 20 6
gen zone cyl p0 0. 0. 0. p1 4.5 0. 0. p2 0. 40. 0. p3 0. 0. 4.5 p4 4.5 40. 0. p5 0. 40. 4.5 size 5 20 9 ratio 1 1 1 group rock3
gen zone cyl p0 0. 0. 0. p1 3.897114 0. -2.25 p2 0. 40. 0. p3 4.5 0. 0. p4 3.897114 40. -2.25 p5 4.5 40. 0 size 5 20 3 ratio 1 1 1 group rock3
gen zone cyl p0 0. 0. 0. p1 0. 0 -3.20 p2 0. 40. 0. p3 3.897114 0. -2.25 p4 0 40. -3.2 p5 3.897114 40. -2.25 size 5 20 6 ratio 1 1 1 group rock3
gen zon radcyl p0 0 0 0 p1 20.0 0 0 p2 0 40 0 p3 0 0 20 size 5 20 9 8 dim 8.7. 8.7. 8.7. 8.7 ratio 1 1 1 1.2
gen zon radcyl p0 0 0 0 p1 20.0 0 -11.547005 p2 0 40 0 p3 20 0 0 p4 20 40 -11.547005 p5 20 40 0 p6 20 0 -4 p7 20 40 -4 p8 7.534421 0 -4.350 p9 8.7 0 0 p10 7.534421 40 -4.35 p11 8.7 40 0 size 5 20 3 8 ratio 1 1 1 1.2
gen zon radcyl p0 0 0 0 p1 0 0 -20 p2 0 40 0 p3 20 0 -11.547005 p4 0 40 -20 p5 20 40 -11.547005 p6 20 0 -20 p7 20 40 -20 p8 0 0 -7.4 p9 7.534421 0 -4.35 p10 0 40 -7.40 p11 7.534421 40 -4.35 size 5 20 6 8 ratio 1 1 1 1.2
gen zon reflect normal -1 0 0
mo mohr
pro bulk 1.86e8 shear 1.75e8 fric 29 coh 5e5 ten 0.2e6 range z -20 20
ini dens=2780
set grav 0 0 -10
fix z range z -20.0001 -19.9999
fix x range x -20.0001 -19.9999
fix x range x 19.9999 20.0001
fix y range y -0.0001 0.0001
fix y range y 39.9999 40.0001
apply szz -1.0286e6 range z 19.9999 20.0001
ini szz -1.0286e6 grad 0 0 27800
ini syy -3.39438e5 grad 0 0 9174
ini sxx -3.39438e5 grad 0 0 9174
hist unbal
plot hist 1
solve
save step1.sav
算的时候收敛,而且SYY和YDISP也比较好
开挖计算
model null range group rock3;开挖核心部分
model null range group rock2;二期支护处开挖围岩
model null range group rock1;初期支护处开挖围岩
def a1
x1=0.0
x2=0.0
z1=0.0
z2=0.0
y1=0.0
loop i(1,7)
y1=5.0*i
loop n(-2,22)
x1=5.2*cos((n-1)*0.17454167)
z1=5.2*sin((n-1)*0.17454167)
x2=8.7*cos((n-1)*0.17454167)
z2=8.7*sin((n-1)*0.17454167)
command
sel cable id i begin x1 y1 z1 end x2 y1 z2 nseg 5
end_command
end_loop
end_loop
end
a1
sel cable prop emod 2.0e10 ytension 8.0e4 xcarea 3.8e-4 &
gr_coh 2e5 gr_k 2.0e7 gr_per 0.3
range name ex1 group rock1 any
model elastic range ex1
prop s=1.15e10 b=9.5e8 range ex1
range name ex2 group rock2 any
model elastic range ex2
prop s=1.64e10 b=1.36e10 range ex2
hist reset;
hist unbal;
solve
save excav.sav
我算动力时,是在计算了开挖之后,算从模型底部往上传播的地震波,也就是沿着Z轴正方向
conf dyn
;进行动力分析
set dyn on
set log on
ini xvel 0 yvel 0 zvel 0
ini xdis 0 ydis 0 zdis 0
ini state 0
free x y z ran z -20.0001 -19.9999
;动力边界条件
tab 1 read zv.txt
ini dens=2780
sel cable prop dens=3000
apply ff
set dyn multi on ;加快运算速度
apply zacc 1.0 hist table 1 ran z -20.0001 -19.9999
hist reset
hist dytime ;
set dyn damp local 0.2
set dyn dt 9.999e-6
sol age 5
save dynam1.sav
但是lakewater你不是说加了apply ff后其他情况的约束自动消除,只剩下波的传播方向才有约束吗,但是 |
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