原帖由 byb 于 2007-8-19 23:42 发表
贴一段简化过的命令。
*dim,x1,,7
*dim,pradius,,7
*dim,degree,,7
x1(1)=80.5,76.9,72,68,64.4,62.4,60
h=8
pradius(1)=56,56,48,43,40,38,38
degree(1)=8,16,32,48,64,76,83
*dim,lnumber5,,7
...
Maybe, I don't understand what you expect fully. Try to test the following APDL for you:
*dim,x1,,7
*dim,pradius,,7
*dim,degree,,7
x1(1)=80.5,76.9,72,68,64.4,62.4,60
h=8
pradius(1)=56,56,48,43,40,38,38
degree(1)=8,16,32,48,64,76,83
*dim,lnumber5,,7
/prep7
*afun,deg
*do,i,1,7,1
k,,x1(i),h/2,-(i-1)*800
k,,x1(i),h/2+pradius(i),-(i-1)*800
circle,kp(x1(i),h/2+pradius(i),-(i-1)*800),,,kp(x1(i),h/2,-(i-1)*800),degree(i),1
alls
*get,_return,line,0,num,max, !!! it depends
lnumber5(i)=_return
*enddo
finish
[ 本帖最后由 jinqinghai 于 2007-8-20 00:08 编辑 ] |