ansys经典例子-循环对称结构模态分析

XU200810100659

r1=5 !建模

r2=10
d1=2
nsect=24
alpha_deg=360/nsect
alpha_rad=2*acos(-1)/nsect

/prep7
csys,1
k,1,0,0,0
k,2,0,0,d1
k,3,r1,0,0
k,4,r1,0,d1
l,3,4
arotat,1,,,,,,1,2,alpha_deg/2
k,7,r2,0,0
k,8,r2,0,d1
l,7,8
arotat,5,,,,,,1,2,alpha_deg/2
arotat,2,,,,,,1,2,alpha_deg/2
arotat,6,,,,,,1,2,alpha_deg/2
a,5,6,10,9
mshkey,1
et,1,181
r,1,0.20
r,2,0.1
mp,ex,1,10e6
mp,prxy,1,0.3
mp,dens,1,1e-4
esize,0.5
asel,,,,1,4
aatt,,1
asel,,,,5
aatt,,2
allsel

CYCLIC, , , ,'CYCLIC' !定义基本扇区

AMESH,all !分网

FINISH

/SOL !求模态解

ANTYPE,2
MODOPT,LANB,10
MXPAND,10, , ,0
PSTRES,0
MODOPT,LANB,10,0,0, ,OFF
DK,5, , , ,0,UZ, , , , , ,
SOLVE
FINISH

/POST1
SET,LIST
SET, , ,1, , , ,4,
/CYCEXPAND, ,ON
PLNS,U,SUM !观察扩展模态

FINISH

ldhltw

很是不错，看看

Wallace998

谢谢分享！！