【原创】请教:关于*Static, stabilize 的问题

silt

我分析地基的变形问题。当地基的变形较大时（可能接近破坏），计算收敛很慢，然后中断。
   我采用*Static, stabilize=0.0002，计算可以在进行几步，但结果显然不对，请大侠帮分析分析。
  ...
**  
*Step, name=Step-5, unsymm=YES
*Static, stabilize=0.0002
.......
  
先谢谢！

silt

time=8以后的结果是 sablization is active

gestapo

my the experience on stabilize is shown as below:  
1. it is as posisble as that you don't use paramenter stabilize.  
2. the more the stablize value is, the more difference between practice vale and calculation value.  
3. it will results the calculation value of the force/permanent set/ect bigger than practice value.

silt

gestapo wrote:
my the experience on stabilize is shown as below:  
   
2. the more the stablize value is, the more difference between practice vale and calculation value.  
3. it will results the calculation value of the force/permanent set/ect bigger than practice value.  

  
先谢谢gestapo大侠。
麻烦解释解释后面两条，practice vale and calculation value分别指什么？

silt

我的INP文件的相关设定，不知对否？请帮看看．
  
** STEP: Step-9
*Step, name=Step-9, unsymm=YES
*Static, stabilize=1e-05
0.0005, 1., 1e-07, 0.05
** BOUNDARY CONDITIONS

gestapo

實際值及計算值。
the input file is ok