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发表于 2004-4-17 13:00:59
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来自 江西南昌
回复: 【讨论】有关于UMAT的简单问题
谢谢kivinchoa 和wpengw123 两位大侠指教,但我在运行abaqus6.3手册上的umat范例时,一点也没改动,可是始终没有调用子程序,不知在哪儿出了错,请哪位大侠帮忙指正一下,浪费您的时间,实在是抱歉!!!!手册上的例子为: umatmst3.inp
*HEADING
UMAT - MISES PLASTICITY, UNIAXIAL TENSION TEST, C3D8 ---
*NODE,NSET=ALLN
1,0.,0.,0.
2,1.,0.,0.
3,1.,1.,0.
4,0.,1.,0.
5,0.,0.,1.
6,1.,0.,1.
7,1.,1.,1.
8,0.,1.,1.
*NODE,NSET=ALLN1
11,0.,0.,0.
12,1.,0.,0.
13,1.,1.,0.
14,0.,1.,0.
15,0.,0.,1.
16,1.,0.,1.
17,1.,1.,1.
18,0.,1.,1.
*ELEMENT,TYPE=C3D8,ELSET=ALLE
1,1,2,3,4,5,6,7,8
*ELEMENT,TYPE=C3D8,ELSET=ALLE1
10,11,12,13,14,15,16,17,18
*SOLID SECTION,ELSET=ALLE,MATERIAL=ALLE
*SOLID SECTION,ELSET=ALLE1,MATERIAL=ALLE1
*MATERIAL,NAME=ALLE
*USER MATERIAL,CONSTANTS=8
200.E3,.3,200.,0.,220.,.0009,220.,.0029
*DEPVAR
13,
*MATERIAL,NAME=ALLE1
*USER MATERIAL,CONSTANTS=8,UNSYMM,TYPE=MECHANICAL
200.E3,.3,200.,0.,220.,.0009,220.,.0029
*DEPVAR
13,
*BOUNDARY
1,PINNED
2,2
5,2
6,2
4,1
5,1
8,1
2,3
3,3
4,3
11,PINNED
12,2
15,2
16,2
14,1
15,1
18,1
12,3
13,3
14,3
*STEP,NLGEOM,INC=20
*STATIC,DIRECT
1.,20.
*BOUNDARY
7,3,,.004
5,3,,.004
6,3,,.004
8,3,,.004
*EL PRINT
S,
SINV,
E,
EE,
SDV,
*NODE PRINT
U,RF
*EL FILE,FREQ=10
S,E,SDV
*END STEP
*STEP,NLGEOM,INC=20,UNSYMM=YES
*STATIC,DIRECT
1.,20.
*BOUNDARY
17,3,,.004
15,3,,.004
16,3,,.004
18,3,,.004
*END STEP
SUBROUTINE UMAT(STRESS,STATEV,DDSDDE,SSE,SPD,SCD,
1 RPL,DDSDDT,DRPLDE,DRPLDT,STRAN,DSTRAN,
2 TIME,DTIME,TEMP,DTEMP,PREDEF,DPRED,MATERL,NDI,NSHR,NTENS,
3 NSTATV,PROPS,NPROPS,COORDS,DROT,PNEWDT,CELENT,
4 DFGRD0,DFGRD1,NOEL,NPT,KSLAY,KSPT,KSTEP,KINC)
C
INCLUDE 'ABA_PARAM.INC'
C
CHARACTER*80 MATERL
DIMENSION STRESS(NTENS),STATEV(NSTATV),
1 DDSDDE(NTENS,NTENS),DDSDDT(NTENS),DRPLDE(NTENS),
2 STRAN(NTENS),DSTRAN(NTENS),TIME(2),PREDEF(1),DPRED(1),
3 PROPS(NPROPS),COORDS(3),DROT(3,3),
4 DFGRD0(3,3),DFGRD1(3,3)
C
DIMENSION EELAS(6),EPLAS(6),FLOW(6)
 ARAMETER (ONE=1.0D0,TWO=2.0D0,THREE=3.0D0,SIX=6.0D0)
DATA NEWTON,TOLER/10,1.D-6/
C
C -----------------------------------------------------------
C UMAT FOR ISOTROPIC ELASTICITY AND ISOTROPIC PLASTICITY
C J2 FLOW THEORY
C CAN NOT BE USED FOR PLANE STRESS
C -----------------------------------------------------------
C PROPS(1) - E
C PROPS(2) - NU
C PROPS(3) - SYIELD
C CALLS AHARD FOR CURVE OF SYIELD VS. PEEQ
C -----------------------------------------------------------
C
IF (NDI.NE.3) THEN
WRITE(6,1)
1 FORMAT(//,30X,'***ERROR - THIS UMAT MAY ONLY BE USED FOR ',
1 'ELEMENTS WITH THREE DIRECT STRESS COMPONENTS')
ENDIF
C
C ELASTIC PROPERTIES
C
EMOD=PROPS(1)
ENU=PROPS(2)
IF(ENU.GT.0.4999.AND.ENU.LT.0.5001) ENU=0.499
EBULK3=EMOD/(ONE-TWO*ENU)
EG2=EMOD/(ONE+ENU)
EG=EG2/TWO
EG3=THREE*EG
ELAM=(EBULK3-EG2)/THREE
C
C ELASTIC STIFFNESS
C
DO 20 K1=1,NTENS
DO 10 K2=1,NTENS
DDSDDE(K2,K1)=0.0
10 CONTINUE
20 CONTINUE
C
DO 40 K1=1,NDI
DO 30 K2=1,NDI
DDSDDE(K2,K1)=ELAM
30 CONTINUE
DDSDDE(K1,K1)=EG2+ELAM
40 CONTINUE
DO 50 K1=NDI+1,NTENS
DDSDDE(K1,K1)=EG
50 CONTINUE
C
C CALCULATE STRESS FROM ELASTIC STRAINS
C
DO 70 K1=1,NTENS
DO 60 K2=1,NTENS
STRESS(K2)=STRESS(K2)+DDSDDE(K2,K1)*DSTRAN(K1)
60 CONTINUE
70 CONTINUE
C
C RECOVER ELASTIC AND PLASTIC STRAINS
C
DO 80 K1=1,NTENS
EELAS(K1)=STATEV(K1)+DSTRAN(K1)
EPLAS(K1)=STATEV(K1+NTENS)
80 CONTINUE
EQPLAS=STATEV(1+2*NTENS)
C
C IF NO YIELD STRESS IS GIVEN, MATERIAL IS TAKEN TO BE ELASTIC
C
IF(NPROPS.GT.2.AND.PROPS(3).GT.0.0) THEN
C
C MISES STRESS
C
SMISES=(STRESS(1)-STRESS(2))*(STRESS(1)-STRESS(2)) +
1 (STRESS(2)-STRESS(3))*(STRESS(2)-STRESS(3)) +
1 (STRESS(3)-STRESS(1))*(STRESS(3)-STRESS(1))
DO 90 K1=NDI+1,NTENS
SMISES=SMISES+SIX*STRESS(K1)*STRESS(K1)
90 CONTINUE
SMISES=SQRT(SMISES/TWO)
C
C HARDENING CURVE, GET YIELD STRESS
C
NVALUE=NPROPS/2-1
CALL AHARD(SYIEL0,HARD,EQPLAS,PROPS(3),NVALUE)
C
C DETERMINE IF ACTIVELY YIELDING
C
IF (SMISES.GT.(1.0+TOLER)*SYIEL0) THEN
C
C FLOW DIRECTION
C
SHYDRO=(STRESS(1)+STRESS(2)+STRESS(3))/THREE
ONESY=ONE/SMISES
DO 110 K1=1,NDI
FLOW(K1)=ONESY*(STRESS(K1)-SHYDRO)
110 CONTINUE
DO 120 K1=NDI+1,NTENS
FLOW(K1)=STRESS(K1)*ONESY
120 CONTINUE
C
C SOLVE FOR EQUIV STRESS, NEWTON ITERATION
C
SYIELD=SYIEL0
DEQPL=0.0
DO 130 KEWTON=1,NEWTON
RHS=SMISES-EG3*DEQPL-SYIELD
DEQPL=DEQPL+RHS/(EG3+HARD)
CALL AHARD(SYIELD,HARD,EQPLAS+DEQPL,PROPS(3),NVALUE)
IF(ABS(RHS).LT.TOLER*SYIEL0) GOTO 140
130 CONTINUE
WRITE(6,2) NEWTON
2 FORMAT(//,30X,'***WARNING - PLASTICITY ALGORITHM DID NOT ',
1 'CONVERGE AFTER ',I3,' ITERATIONS')
140 CONTINUE
EFFHRD=EG3*HARD/(EG3+HARD)
C
C CALC STRESS AND UPDATE STRAINS
C
DO 150 K1=1,NDI
STRESS(K1)=FLOW(K1)*SYIELD+SHYDRO
EPLAS(K1)=EPLAS(K1)+THREE*FLOW(K1)*DEQPL/TWO
EELAS(K1)=EELAS(K1)-THREE*FLOW(K1)*DEQPL/TWO
150 CONTINUE
DO 160 K1=NDI+1,NTENS
STRESS(K1)=FLOW(K1)*SYIELD
EPLAS(K1)=EPLAS(K1)+THREE*FLOW(K1)*DEQPL
EELAS(K1)=EELAS(K1)-THREE*FLOW(K1)*DEQPL
160 CONTINUE
EQPLAS=EQPLAS+DEQPL
SPD=DEQPL*(SYIEL0+SYIELD)/TWO
C
C JACOBIAN
C
EFFG=EG*SYIELD/SMISES
EFFG2=TWO*EFFG
EFFG3=THREE*EFFG2/TWO
EFFLAM=(EBULK3-EFFG2)/THREE
DO 220 K1=1,NDI
DO 210 K2=1,NDI
DDSDDE(K2,K1)=EFFLAM
210 CONTINUE
DDSDDE(K1,K1)=EFFG2+EFFLAM
220 CONTINUE
DO 230 K1=NDI+1,NTENS
DDSDDE(K1,K1)=EFFG
230 CONTINUE
DO 250 K1=1,NTENS
DO 240 K2=1,NTENS
DDSDDE(K2,K1)=DDSDDE(K2,K1)+FLOW(K2)*FLOW(K1)
1 *(EFFHRD-EFFG3)
240 CONTINUE
250 CONTINUE
ENDIF
ENDIF
C
C STORE STRAINS IN STATE VARIABLE ARRAY
C
DO 310 K1=1,NTENS
STATEV(K1)=EELAS(K1)
STATEV(K1+NTENS)=EPLAS(K1)
310 CONTINUE
STATEV(1+2*NTENS)=EQPLAS
C
RETURN
END
C
C
SUBROUTINE AHARD(SYIELD,HARD,EQPLAS,TABLE,NVALUE)
C
INCLUDE 'ABA_PARAM.INC'
DIMENSION TABLE(2,NVALUE)
C
C SET YIELD STRESS TO LAST VALUE OF TABLE, HARDENING TO ZERO
SYIELD=TABLE(1,NVALUE)
HARD=0.0
C
C IF MORE THAN ONE ENTRY, SEARCH TABLE
C
IF(NVALUE.GT.1) THEN
DO 10 K1=1,NVALUE-1
EQPL1=TABLE(2,K1+1)
IF(EQPLAS.LT.EQPL1) THEN
EQPL0=TABLE(2,K1)
IF(EQPL1.LE.EQPL0) THEN
WRITE(6,1)
1 FORMAT(//,30X,'***ERROR - PLASTIC STRAIN MUST BE ',
1 'ENTERED IN ASCENDING ORDER')
CALL XIT
ENDIF
C
C CURRENT YIELD STRESS AND HARDENING
C
DEQPL=EQPL1-EQPL0
SYIEL0=TABLE(1,K1)
SYIEL1=TABLE(1,K1+1)
DSYIEL=SYIEL1-SYIEL0
HARD=DSYIEL/DEQPL
SYIELD=SYIEL0+(EQPLAS-EQPL0)*HARD
GOTO 20
ENDIF
10 CONTINUE
20 CONTINUE
ENDIF
RETURN
END |
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