请教：界面点问题

stonebit2004

转载一下关于空洞界面点的方法和相应的例子。
在柔性体的转动中心（与刚性体的联接处）必须有节点存在，此节点在ADAMS中将作为外部节点使用，如果在联接处柔性体为空洞，则需在此处创建一节点,并使用刚性区域处理此节点（外部节 点）与其接处柔性体为空洞，则需在此处创建一节点,并使用刚性区域（用cerig和*repeat命令）处理此节点（外部节 点）与其周围的节点。
一例子命令流如下：
/title, ADAMS interface - simple connecting rod with constraint equations
c*** This represents a connecting rod using the following features:
c*** SOLID45 to represent the rod
c*** constraint equations to represent the pin
c*** MASS21 for the pin center

/units,bin
pi = 3.14159
/prep7
c*** define rod width, length and pin radii (all in meters)
w=.015
w=.015
l=.225
r1=.0125
r2=.025

c*** convert to inches
w=w*39.37
l=l*39.37
r1=r1*39.37
r2=r2*39.37
mp,ex,,2.1e9*1.45e-4
mp,nuxy,,.3
mp,dens,,7800*1.94e-3/12**3/12
! convert to "pound_mass" inch-based slug

c*** define pins
et,2,mass21
r,2, .001*.06852,.001*.06852,.001*.06852
type,2
real,2
n,2000
n,2001,,,.225*39.37
e,2000
e,2001
e,2001
c*** define connecting rod - take into account pin radii

et,1,45
type,1
real,1
n,1,-w/2,-w/2,r1
n,2,w/2,-w/2,r1
ngen,2,2,1,2,1,,w
ngen,11,10,1,4,1,,,(l-r2-r1)/10
e,1,2,4,3, 11,12,14,13
egen,10,10,-1

c*** pins are rigid - use constraint equations
cerig,2000,1
*repeat,4,,1
cerig,2001,101
*repeat,4,,1

c*** delete rotational CE's (to get clean run)
cedel,4,6
*repeat,8,6,6
finish
finish
c*** select pin nodes and compute data for ADAMS interface
nsel,s,node,,2000, 2001,1
adams,6
! end of sample input test