以下是我的分析方案:
按照制动鼓工作的方式,可将其视为:首先,施加促动力,接触面产生接触压力;其次制动鼓转动,接触压力分布发生变化,制动摩擦使动能转换为热能,制动器温度发生变化。
在整个过程中,制动鼓的转动是一个不稳定的状态,属于瞬态分析的过程。将制动过程用以下载荷步来模拟。
第一个载荷步:施加凸轮的促动力,此载荷步模拟制动蹄片压向制动鼓的工作过程;
第二个载荷步:对鼓施加转动位移,使制动鼓与摩擦片的接触面上有相对的滑动;
我利用接触向导,建立了柔体-柔体接触,这是部分程序:我先作第一个载荷步,只是加上促动力,制动鼓没有转动时的结果,不收敛!
/COM, CONTACT PAIR CREATION - START
CM,_NODECM,NODE
CM,_ELEMCM,ELEM
CM,_KPCM,KP
CM,_LINECM,LINE
CM,_AREACM,AREA
CM,_VOLUCM,VOLU
MP,MU,3,0.3
MAT,3
R,3 !在此R的设置,怎么确定??
REAL,3
ET,4,170
ET,5,174
R,3,,,1.0,0.1,0,
RMORE,,,1.0E20,0.0,1.0,
RMORE,0.0,0,1.0,,1.0,0.5
RMORE,0,1.0,1.0,0.0,,1.0
KEYOPT,5,4,0
KEYOPT,5,5,0
NROPT,UNSYM
KEYOPT,5,7,2
KEYOPT,5,8,0
KEYOPT,5,9,0
KEYOPT,5,10,0
KEYOPT,5,11,0
KEYOPT,5,12,0
KEYOPT,5,2,0
KEYOPT,4,5,0
! Generate the target surface
ASEL,S,,,291
ASEL,A,,,305
CM,_TARGET,AREA
TYPE,4
NSLA,S,1
ESLN,S,0
ESURF
CMSEL,S,_ELEMCM
! Generate the contact surface
ASEL,S,,,18
ASEL,A,,,24
CM,_CONTACT,AREA
TYPE,5
NSLA,S,1
ESLN,S,0
ESURF
ALLSEL
ESEL,ALL
ESEL,S,TYPE,,4
ESEL,A,TYPE,,5
ESEL,R,REAL,,3
/PSYMB,ESYS,1
/PNUM,TYPE,1
/NUM,1
EPLOT
ESEL,ALL
ESEL,S,TYPE,,4
ESEL,A,TYPE,,5
ESEL,R,REAL,,3
/COM, CONTACT PAIR CREATION - END
/MREP,EPLOT
CSYS,1
ASEL,S,,,288
ASEL,A,,,302
NSLA,S,1
D,ALL,UZ,0
ALLSEL,ALL
ASEL,S,,,42
NSLA,S,1
D,ALL,UX,0
D,ALL,UZ,0
ALLSEL,ALL
DA,250,SYMM
DA,278,SYMM
F,7876,FY,32067
ANTYPE,0
NLGEOM,1
autots,1
nsubst,100,1000,50
NROPT,UNSYM
!SOLVE
我想问版主,最后antype以后的程序这么设置是否合理?应该考虑什么?
有劳版主了 !!!!! |