（高手指教）通过热分析然后得到的热损耗与手动计算的为什么差别这么大？

longkaifeng1hao

下面是写的命令流，算热损耗的时候是用生热率乘以体积来得到的
手动算是用温差出热阻得到
/FILNAME,VAPORCELL EXERCISE1
/TITLE,STEADY THERMAL ANALYSIS ON THE VAPORCELL EXERCISE1
/UNITS,SI
KEYW,PR_THERM1
！
/PREP7
ET,1,SOLID70
et,2,link33
r,2,160e-12
et,3,link33
r,3,3.7e-9
MP,KXX,1,1.5
MP,DENS,1.23E3
MP,C,1,800
MP,KXX,2,157
MP,DENS,2,2.4E3
MP,C,2,700
MP,KXX,3,0.0259
MP,DENS,3,1.205
MP,C,3,716
mp,kxx,4,0.2
mp,kxx,5,317
！材料定义
！建模
BLOCK,0,1e-3,0,1e-3,0,100e-6
wpoffs,,,100e-6
block,0,1e-3,0,1e-3,0,500e-6
wpoffs,,,500e-6
block,0,1e-3,0,1e-3,0,1e-3
wpoffs,,,1e-3
block,0,1e-3,0,1e-3,0,500e-6
wpoffs,,,500e-6
block,0,1e-3,0,1e-3,0,100e-6
wpoffs,,,100e-6
block,0,1e-3,0,1e-3,0,1e-3
block,0.1e-3,0.9e-3,0.1e-3,0.9e-3,0,1e-3
vsbv,6,7
wpoffs,,,1e-3
block,0,1e-3,0,1e-3,0,1e-3
wpoffs,,,1e-3
block,0,1e-3,0,1e-3,0,1e-3
block,0.1e-3,0.9e-3,0.1e-3,0.9e-3,0,1e-3
vsbv,7,9
wpoffs,,,1e-3
block,-1e-3,1e-3,-1e-3,1e-3,0,0.1e-3
wpoffs,,,-5.2e-3
block,0,1e-3,0,1e-3,0,-1e-3
block,0.1e-3,0.9e-3,0.1e-3,0.9e-3,0,-1e-3
vsbv,9,11
wpoffs,,,-1e-3
block,-1e-3,1e-3,-1e-3,1e-3,0,-0.1e-3
wpoffs,,,1e-3
vglue,all
kl,87,0.8,151
l,31,151
l,151,70
/pnum,volu,1
vplot,all
numcmp,all
vplot,all
MSHAPE,1,3-D
MSHKEY,0
!网格划分
mat,3
esize,0.1e-3
vmesh,2
mat,1
esize,0.1e-3
vmesh,1,3,2
mat,1
esize,0.1e-3
vmesh,4,5
mat,2
esize,0.1e-3
vmesh,6,7
mat,1
esize,0.1e-3
vmesh,8
mat,4
esize,0.1e-3
vmesh,9,11,2
mat,1
esize,0.1e-3
vmesh,10
mat,5
type,2
esize,0.1e-3
lmesh,13
mat,5
type,3
esize,0.1e-3
lmesh,14
allsel
eplot
finish
!求解
/solu
antype,static
vsel,s,,,4,5,1
nslv,s,1
bf,all,hgen,22.5e6
asel,s,,,17
nsla,s,1
d,all,temp,20
asel,s,,,24
nsla,s,1
d,all,temp,20
allsel
solve
finish
!后处理
/post1
/plopts,info,on
plnsol,temp

longkaifeng1hao

应该是温差除以热阻