- 积分
- 3
- 注册时间
- 2007-12-17
- 仿真币
-
- 最后登录
- 1970-1-1
|
发表于 2012-4-27 23:53:41
|
显示全部楼层
来自 荷兰
whskycom 发表于 2012-4-5 07:28 
现举一个简单例子,如下:
例子:有一个初始为1*1*1的立方体,step1结束后此立方体变为1*2*0.5,step2结 ...
1) 不必相等
2)我想应该是可以的,毕竟最终ABAQUS 所需要的只是inp文件,之前的过程类似“black box”吧,
3)参考用户手册:
Solution mapping operates by interpolating results from nodes in the old mesh to points (either nodes or integration points) in the new mesh. The first step, therefore, involves associating solution variables with nodes in the old mesh. For nodal solution variables, such as nodal temperature or pore pressure, the association is already made. For integration point variables Abaqus obtains the solution variables at the nodes of the old mesh by extrapolating values from the integration points to the nodes of each element and then averaging these values over all similar elements abutting each node.
Next, the location of each point in the new mesh is obtained with respect to the old mesh. The new mesh points include integration points in all cases and nodes in procedures that record nodal state in addition to displacements (for example, nodal temperatures in coupled temperature-displacement procedures).
The element (in the old mesh) in which the point lies is found, and the point's location in that element is obtained. (This procedure assumes that all points in the new mesh lie within the bounds of the old mesh: warning messages are issued if this is not so, and the values of the variables are set to zero.)
The variables are then interpolated from the nodes of the old element to the points in the new model.
All necessary variables are interpolated automatically in this way so that the solution can proceed with the new mesh. |
|